- #1

- 11

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check that, for any nxn matrices A,B then rank(AB) (> or =) rank A +rank(B)-n

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- Thread starter bernoli123
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- #1

- 11

- 0

check that, for any nxn matrices A,B then rank(AB) (> or =) rank A +rank(B)-n

- #2

- 77

- 0

Are you familiar with the Rank-Nullity Theorem?

- #3

HallsofIvy

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